Level 1- Mixed Graph Practice Quiz -2 Easy

The Population of Various States in a Certain Year.

The angles subtended at the center of the circle by different sectors are shown in degrees. The percentage of the total population represented by that sector.

Total Population = 60, 00,000.

The table below gives a gender-wise and literacy wise population ratio. Study the pie chart and the table and answer the questions that follow:

 State Gender Ratio Male: Female Literacy Ratio Literate: Illiterate A 4: 3 9: 4 B 5: 3 8: 5 C 3: 2 9: 5 D 3: 5 7: 3 E 9: 7 5: 2 F 3: 1 1: 3 G 7: 9 2: 1

(2.1) What is the approximate total of literates of States ‘B’ and ‘D’ together?

(a) 1288835
(b) 1289538
(c)  690462
(d) 694026
(e) None of these.

Ans:- B

Solution: (literates of B) + (literates of D)
=> [(19 × 8/13) + (14 ×7/10)] × 60, 000.
=> [152 +1274] ×60, 000/130.
=> 1426 ×6000/13.
= 1289538

(2.2)  The number of females in ‘A’, ‘C’ and ‘E’ is what percentage of the total population of all the above states (‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, ‘G’)?

(a) 12.91%.
(b) 42.13%
(c) 21.91%
(d) 24.13%.
(e) None of these.

Ans:- c

Solution:
Convert Degrees into percentage
Population of A = [82.8/360] ×100 = 23%
Population of C = [61.2/360] ×100 = 17%
Population of E = [43.2/360] ×100 = 12%
Females of A, C & E = [(23 × 3/7) + (17×2/5) + (12 ×7/16)]/100 × 60, 00, 000

No. of females of A, C & E is what % of total population
= [(69/7 + 34/5 + 84/16)/100] × 60, 00, 000/60, 00, 000
= [(69×80) + (102×34) + (35×84)/ (560)]/100
= [11928/560] × 100 = 21.91%

(2.3) If there be a decrease of 4% in the population of ‘E’ and an increase of 3% in the population of ‘F’, in the next year over the respective population of ‘F’ in the next year will be

(a) 163:128
(b) 125:101
(c) 123:103
(d) 128:103
(e) None of these.

Ans:- D

Solution:
Present population of E = [43.2/360] ×6000000 = 7, 20, 000.
4% of 720000 = 28, 800.
Therefore, population of E next year = 7, 20, 000 – 28, 800 = 6, 91, 200
Present population of F = 9% of total population = 60, 00, 000 × 9/100 = 5, 40, 000
3% of population = 16, 200.
Therefore, population of F next year = 5, 40, 000 + 16, 200 = 5, 56, 200.
Therefore, Ratio of the population of E to the population of F next year
= 691200: 556200
= 128: 103 (approx.)

(2.4) The number of females in state F is approximately what percentage of the number of females in state ‘G’?

(a) 66.67%.
(b) 69.83%.
(c) 76.66%.
(d) 60.67%.
(e) None of these.

Ans:- A

Solution:
The population of State F = 9% of the total population = 5, 40, 000.
= 9% of the total population = 5, 40, 000.
Therefore, number of females in State F = 540000 × 1/ 4.
= 1, 35, 000.
The population of Stage G
= 6% of the total population = 3, 60, 000
Therefore, number of females in stage G = 3, 60, 000 × 9/16 = 2, 02, 500.
Therefore, number of females in State F = ((135000/ 202500) × 100)
= 66.67%

(2.5) If 68.8% of the females and 72% of the males are literate in state ‘D’, then the ratio of male literates to female literates in that state is,

(a) 109: 329
(b) 189: 301
(c)  131: 301
(d) 103: 329
(e) None of these.

Ans:- B

Solution: Population of State D = 14% of the total population = 8, 40, 000
Male: Female ratio is 3:5
Therefore, number of males = 840000 × 3/8 = 3, 15, 000
Therefore, number of females = 840000 × 5/8 = 5, 25, 000
72% of males is 2, 26,800.
68.8% of females are 3, 61,200.
Therefore, the ratio of male literates to female literates is 226800:361200 or
189: 301.

(2.6) What is the ratio of the illiterates of State ‘A’ to those of State ‘G’ approximately?

(a) 177: 50.
(b) 137: 65
(c) 183: 71
(d) 127: 73
(e) None of these.

Ans:- A

Explanation:
Population of State A = 13, 80, 000.
Therefore, illiterates in State A
= 1380000 × 4/13 = 4, 24, 615.
Population of State G = 3, 60, 000
Therefore, illiterates in State G
360000 × 1/3 = 1, 20, 000

Illiterates in State A: Illiterates in State G = 177:50 (approx.)