Level-3 Mixed Graph Practice Test -2 Hard

Directions : Study the following pie and table chart carefully and answer the questions given below.

A person travels daily for 8 hours for 5 days to cover a certain distance. The following pie chart shows the percentage of total distance travelled by him in 5 different modes on day1 (M1, M2, M3, M4, and M5) and the percentage of distance travelled by him with the same modes remained the same as each day of the journey.

The table shows speed of M5 each day and the time it took to travel using M5 out of total travelling time that day.

Days Speed of M5 (kmph) Time taken by M5 each day as % of total travel time
1 40 6.25
2 60 12.5
3 68 3.125
4 72 8.33
5 120 16.67

1 What is the sum of the total distance travelled by the person during the given five days?

» Explain it
Correct Option: C
From common explanation we have

Total distance = A + B + C + D + E

= 30500/15 = 2033 1/3 km
Hence, option C is correct.

Common explanation : 

Days Time taken by M5 each day as % of total travel time 8 hour travelling each day
1 6.25 6.25% of 8 = 30 min
2 12.5 1 hour
3 3.125 15 min
4 8.33 40 min
5 16.67 1 h 20 min

 

From the table given in the question and above,

Distance = speed × time = 40 × 1/2 = 20 km
From pie chart, for M5, this is 15% of total distance, so

Total distance, A = 100 × 20/15 km
Similarly, we calculate for each day

B = 100 × 60 /15 km
C = 100 × 17/15km
D = 100 × 48 /15 km
E = 100 × 160/15 km

2 What is difference between the total distance travelled by Mode 2 (M2) in the five days and the total distance travelled by Mode 3 (M3) in the five days?

Correct Option: A
From common explanation, we have

Distance travelled by M3 in five days

25% of A + 25% of B + 25% of C + 25% of D + 25% of E

25% of (A + B + C + D + E)

= 25% of 2033 1/3 km
Similarly, distance travelled by M2 in five days

= 35% of 2033 1/3 km
Difference = 10% of 2033 1/3 km
= 610/3 km = 203 1/3 km
Hence, option A is correct.

Common explanation : 

Days Time taken by M5 each day as % of total travel time 8 hour travelling each day
1 6.25 6.25% of 8 = 30 min
2 12.5 1 hour
3 3.125 15 min
4 8.33 40 min
5 16.67 1 h 20 min

Let from day 1 to day 5 he travels A, B, C, D, and E km respectively,

From the table given in the question and above,

Distance = speed × time = 40 × 1/2 = 20 km
From pie chart, for M5, this is 15% of total distance, so

Total distance, A = 100 × 20/15 km
Similarly, we calculate for each day

B = 100 × 60 /15 km
C = 100 × 17/15 km
D = 100 × 48/15 km
E = 100 × 160/15 km

 

3.The average speed of the person during the first two days is approximately what percent of the average speed of the person during the last three days?
A 13.33%
B 33.33%
C 56.67%
D 53.33%
E 43.33%

Correct Option: D
Total distance in first two days from common explanation

= A + B = 1600/3 km
Total time = 2 × 8 = 16 hours

Average speed = (1600/3)/16 = 100/3 kmph
Similarly, average speed for last three days

= 125/2 kmph
Percentage = (100/3) /(125/2) × 100 = 53.33%

Hence, option D is correct.

Common explanation : 

Days Time taken by M5 each day as % of total travel time 8 hour travelling each day
1 6.25 6.25% of 8 = 30 min
2 12.5 1 hour
3 3.125 15 min
4 8.33 40 min
5 16.67 1 h 20 min

Let from day 1 to day 5 he travels A, B, C, D, and E km respectively,

From the table given in the question and above,

Distance = speed × time = 40 × 1/2 = 20 km
From pie chart, for M5, this is 15% of total distance, so

Total distance, A = 100 × 20/15 km
Similarly, we calculate for each day

B = 100 × 60/15 km
C = 100 × 17 /15km
D = 100 × 48/15 km
E = 100 × 160/15 km

4 Suppose, the person spends 25% of the total time on each day to travel by M1 then the average speed of M1 during the five days is approximately what percent less than the average speed of M5 during the five days?
A 60%
B 75%
C 80%
D 120%
E 100%

Correct Option: B
From common explanation, we have

Total time to travel by M1 in five days = 25% of (5 × 8) = 10 hours

Total distance travelled by M1 in five days = 10% of (A + B + C + D + E)

= 10% of 2033 1/3 = 610/3 km
Average speed of M1 during the five days

= (610/3)/10 = 61/3 kmph
Now, distance travelled using M5 in five days = 15% of of (A + B + C + D + E)

= 15% of 2033 1/3 = 305 km
Time of M5 (from table in common explanation)

= 1/2 hr + 1 hr + 1/4 hr + 2/3 hr + 4 /3hr = 15/4 hr
Average speed = 305/(15/4) = 244/3 kmph
Percentage difference = (244/3 – 61/3)/(244/3) × 100 = 75%
Hence, option B is correct.

Common explanation : 

Days Time taken by M5 each day as % of total travel time 8 hour travelling each day
1 6.25 6.25% of 8 = 30 min
2 12.5 1 hour
3 3.125 15 min
4 8.33 40 min
5 16.67 1 h 20 min

Let from day 1 to day 5 he travels A, B, C, D, and E km respectively,

From the table given in the question and above,

Distance = speed × time = 40 × 1 /2= 20 km
From pie chart, for M5, this is 15% of total distance, so

Total distance, A = 100 × 20/15 km
Similarly, we calculate for each day

B = 100 × 60/15 km
C = 100 × 17/15 km
D = 100 × 48/15 km
E = 100 × 160/15 km

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